1x^2+4x+9=0

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Solution for 1x^2+4x+9=0 equation:


Simplifying
1x2 + 4x + 9 = 0

Reorder the terms:
9 + 4x + 1x2 = 0

Solving
9 + 4x + 1x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-9' to each side of the equation.
9 + 4x + -9 + x2 = 0 + -9

Reorder the terms:
9 + -9 + 4x + x2 = 0 + -9

Combine like terms: 9 + -9 = 0
0 + 4x + x2 = 0 + -9
4x + x2 = 0 + -9

Combine like terms: 0 + -9 = -9
4x + x2 = -9

The x term is 4x.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4x + 4 + x2 = -9 + 4

Reorder the terms:
4 + 4x + x2 = -9 + 4

Combine like terms: -9 + 4 = -5
4 + 4x + x2 = -5

Factor a perfect square on the left side:
(x + 2)(x + 2) = -5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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